[root@localhost ~]# echo $(( 13 % 3 ))
1#注释:这个有没有空格是关键!!
交互式脚本:变量内容由用户决定
[root@localhost ~]# vi sh02.sh
1 #!/bin/bash
2 # Program: 3 # User inputs his first name and last name. Program shows his full name. 4 # History: 5 PATH=/bin:/sbin:/usr/bin:/usr/sbin:/usr/local/bin:/usr/local/sbin:~/bin 6 export PATH 7 read -p "Please input your first name : " firstname 8 read -p "Please input your last name : " lastname 9 echo -e "\nYour full name is :$firstname $lastname "
执行结果
[root@localhost ~]# sh sh02.sh
Please input your first name : GaoPlease input your last name : ZhenanYour full name is :Gao Zhenan
随日期变化:利用日期进行文件的创建:
[root@localhost shelldemo]# cat sh03.sh #!/bin/bash#Program:# creates three files ,which named by user's input# and date command.# History :# 2013/06/10PATH=/bin:/sbin:/usr/bin:/usr/sbin:/usr/local/bin:/usr/local/sbin:~/binexport PATH#1、让用户输入文件名,并取得fileuser这个变量;echo -e "I will use 'touch' command to create 3 files."read -p "Please input your filename: " fileuser#2、为了避免用户随意按【enter】,利用变量功能分析文件名是否有设置filename=${ fileuser:-"filename"}# 3、开始利用date 命令来取得所需要的文件名了。date1=$(date --date='2 days ago' +%Y%m%d)date2=$(date --date='1 days ago' +%Y%m%d)date3=$(date +%Y%m%d)file1=${ filename}${ date1}file2=${ filename}${ date2}file3=${ filename}${ date3}#4、创建文件名touch "$file1"touch "$file2"touch "$file3"
运行结果:
[root@localhost shelldemo]# date
2013年 05月 04日 星期六 07:37:54 CST[root@localhost shelldemo]# sh sh03.sh
I will use 'touch' command to create 3 files.Please input your filename: file[root@localhost shelldemo]# ll总计 8-rw-r--r-- 1 root root 0 05-04 07:39 file20130502-rw-r--r-- 1 root root 0 05-04 07:39 file20130503-rw-r--r-- 1 root root 0 05-04 07:39 file20130504[root@localhost shelldemo]#
数值运算:简单的加减乘除
[root@localhost shelldemo]# vi sh04.sh 1 #!/bin/bash 2 # Program 3 # User inputs 2 integer numbers;program will cross these two numbers. 4 PATH=/bin:/sbin:/usr/bin:/usr/sbin:/usr/local/bin:/usr/local/sbin:~/bin 5 export PATH 6 echo -e "You should input 2 numbers. I will cross them! \n" 7 read -p "first number: " firstnu 8 read -p "second number: " secnu 9 total=$(( $firstnu*$secnu )) 10 echo -e "\nThe result of $firstnu x $secnu is ==> $total"
运行结果:
[root@localhost shelldemo]# sh sh04.sh You should input 2 numbers. I will cross them! first number: 23second number: 2The result of 23 x 2 is ==> 46[root@localhost shelldemo]#
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